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Nov 1, 2025, 18:10:28

I have never bought a single device (laptop, monitor, phone, or tablet) with higher than 60 Hz of display refresh rate, except the most recent device I bought. This one very device has unsolvable dynamic FPS problems, just as what I was afraid of. It is settled. I will never buy devices with high refresh rates again until they finally exit the market.

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Articles

  • Nov 20, 2022

    How to construct mechanics in higher dimensions?

    We can derive the equation of motion for mechanical systems in a Galileo universe with ι\iota time dimensions and χ\chi space dimensions by generalizing the principle of relativity and Hamilton’s principle.

  • Nov 18, 2022

    When a supersonic airplane flies over your head

    Suppose a supersonic airplane has Mach number MM. It flies horizontally. At some time, it flies past over your head at height hh. Then, the distance between you and it when you have just heard it is MhMh.

  • Nov 16, 2022

    Finding curvature radius physically

    Sometimes the curvature radius of a curve can be found by using physical methods although it seems that you must use calculus to find it. In this article, the curvature radius of the curve x2=2pyx^2=2py at the point where the curvature radius is smallest is found by using physical methods without using calculus (with only high school knowledge). The answer is that the smallest curvature is exactly pp, and the point with smallest curvature is the vertex.

  • Nov 16, 2022

    A whirling point charge

    In the vacuum, inside a fixed ring of radius RR with fixed charge QQ uniformly distributed, there is a point charge with charge qq and mass mm moving in the plane of the ring due tue the electrostatic force. It moves in the small region around the center of the ring, and the motion is periodic along a closed curve. The area of the region enclosed by the curve is SS. Denote the distance from the center to the point charge as rr, and r≪Rr\ll R. Find the magnetic induction BB at the center of the ring.

  • Nov 15, 2022

    Solving ODE by recursive integration

    By recursively integrating according to xn+1 ⁣(t)≔∫t0tf ⁣(xn ⁣(s),s) ds+Cx_{n+1}\!\left(t\right)\coloneqq\int_{t_0}^tf\!\left(x_n\!\left(s\right),s\right)\,\mathrm ds+C from x0 ⁣(t0)≔Cx_0\!\left(t_0\right)\coloneqq C, we can get the solution of the ODE x′ ⁣(t)=f ⁣(x ⁣(t),t)x'\!\left(t\right)=f\!\left(x\!\left(t\right),t\right) with initial conditions x ⁣(t0)=Cx\!\left(t_0\right)=C as the limit of the sequence of functions.

  • Nov 13, 2022

    An example of non-uniform elements: heavy elastic rope

    To illustrate the concept about non-uniform elements, we study a simple problem: suppose a uniform heavy elastic rope has mass mm, original length L0L_0, and stiffness kk, and find the mass distribution and length of it when hung vertically. We can use the element method to solve this problem, but the elements are non-uniform in terms of length. The elements add up to get the total length L=mg2k+L0L=\frac{mg}{2k}+L_0.

  • Nov 12, 2022

    Kinetic energy, momentum, and angular momentum of rigid bodies

    In this article, we will find that the inertia matrix naturally appears when we calculate the kinetic energy TT or the angular momentum M\mathbf M of a rigid body. Then, we introduce the concept of principal inertia Jpri\mathbf J_{\mathrm{pri}}. We also study how the inertia matrix changes under translations and rotations and how those transformations may lead to conclusions that can help us simplify the calculation of inertia matrices.

  • Nov 11, 2022

    Hölder means inequality

    The Hölder mean of x⃗\vec x with weights w⃗\vec w and a parameter pp is defined as Mp,w⃗ ⁣(x⃗)≔(w⃗⋅x⃗p)1pM_{p,\vec w}\!\left(\vec x\right)\coloneqq\left(\vec w\cdot\vec x^p\right)^{\frac 1p}, and the value at p=−∞,0,+∞p=-\infty,0,+\infty are defined by the limits. We can prove using Jensen’s inquality that the Hölder mean increases as pp increases. This property can be used to prove HM-GM-AM-QM inequalities.

  • Nov 9, 2022

    A polynomial whose sum of coefficients is a factorial

    The function (1−z)n+1∑k=1∞knzk\left(1-z\right)^{n+1}\sum_{k=1}^\infty k^nz^k is a polynomial of degree nn w.r.t. zz, and the sum of its coefficients is n!n!. This turns out to be properties of Eulerian numbers.

  • Nov 9, 2022

    The image of a circular object through a thin lens

    The image of a circle with radius rr and centered at C(−2f,0)C\left(-2f,0\right) through a thin lens at x=0x=0 with focal length ff and centered at O(0,0)O\left(0,0\right) is a conic section with the focus being (2f,0)\left(2f,0\right), the directrix being line x=fx=f, and the eccentricity being rf\frac rf.

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