Normal vectors of a scalar field
Consider the function , where the domain , and the function is differentiable everywhere.
According to some well-known theories, we can derive that the normal vector of the graph of the function at is .
This gives us an idea that, in fact a conservative field consists of normal vectors of its potential function (a scalar function).
We also know that a scalar function can be derived from its gradient by integrating it along an arbitrary path (what exactly the path is is not important because it is a conservative field, so you can choose one as long as it can make the calculation easy). Here it can come into our minds that we can derive a multi-variable function from its normal vectors.
The method is to make the last component of the normal vectors be and then calculate the integral of the rest components.
I am sorry that the passage is too brief, but I need to have some rest after experiencing several continuous tests today and yesterday. Bless me!